On Mon, 01 Sep 2008 10:52:10 +0200, Manuel Ebert wrote:
> -----BEGIN PGP SIGNED MESSAGE----- > Hash: SHA1 > > Hi Luca, > > use type(something).__name__ , e.g. > > >>> def x(): > >>> pass > >>> class C: > >>> pass > >>> c = C() > >>> type(x).__name__ == 'function' > True > >> type(C).__name__ == 'classobj' > True > >> type(c).__name__ == 'instance' > True That's relatively fragile, since such names aren't reserved in any way. It's easy to fool a name comparison check with an accidental name collision: >>> class function(object): # not a reserved name ... pass ... >>> x = function() >>> type(x).__name__ 'function' >>> x() # must be a function then... Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: 'function' object is not callable But not so easy to fool a type check: >>> type(x) == new.function False Of course that's not bullet-proof either. I leave it as an exercise to discover how you might break that piece of code. -- Steven -- http://mail.python.org/mailman/listinfo/python-list
