Grant Edwards wrote:
On 2008-09-01, W. eWatson <[EMAIL PROTECTED]> wrote:
That's the question in Subject. For example, the difference between
08/29/2008 and 09/03/2008 is +5. The difference between 02/28/2008 and
03/03/2008 is 4, leap year--extra day in Feb. I'm really only interested in
years between, say, 1990 and 2050. In other words not some really strange
period of time well outside our current era of history.
Does the standard library's datetime module not do what you want?
http://docs.python.org/lib/module-datetime.html
Yes, it would seem so. This works fine.
date1 = datetime.date(2007, 2, 27)
date2 = datetime.date(2007, 3, 3)
print "date1: ", date1
print "date2: ", date2
diff = date2 - date1
print "diff: ", diff
result:
date1: 2007-02-27
date2: 2007-03-03
diff: 4 days, 0:00:00
I was pondering this in pyfdate, but perhaps missed it or it was not obvious
to me in the tutorial for some reason. There are few places where it's not
quite complete. pyfdate has some rules for dealing with length of month
oddities that started me thinking it would have difficulty with situations
like the above. However, it would seem any general implementation of time
and date should be capable of making similar calculations without difficulty.
--
W. eWatson
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