What I would do first is to print the result byte by byte each as
hexadecimal number.
If you can I would additionally populate the C-structure with numbers,
which are easier to follow.
Example:
signature = "ABC" // same as 0x41 0x42 0x43
version = 0x61626364
attr_count = 0x65667678
. . .
assuming version == 2 (0x00000002)
the first byte should be 'G' == 0x47 )
if the 4th byte value 2, than you unaligned uint32s and you are little
endian
if the 5th byte is 2, then you have 4 byte aligned uint32s and little endian
if the 7th byte is 2 then you should have unaligned uint32s and big endian
if the 8th byte is 2 then you should have 4 byte aligned uints32 and big
endian
bye
N
Aaron Scott wrote:
I've been trying to tackle this all morning, and so far I've been
completely unsuccessful. I have a binary file that I have the
structure to, and I'd like to read it into Python. It's not a
particularly complicated file. For instance:
signature char[3] "GDE"
version uint32 2
attr_count uint32
{
attr_id uint32
attr_val_len uint32
attr_val char[attr_val_len]
} ... repeated attr_count times ...
However, I can't find a way to bring it into Python. This is my code
-- which I know is definitely wrong, but I had to start somewhere:
import struct
file = open("test.gde", "rb")
output = file.read(3)
print output
version = struct.unpack("I", file.read(4))[0]
print version
attr_count = struct.unpack("I", file.read(4))[0]
while attr_count:
print "---"
file.seek(4, 1)
counter = int(struct.unpack("I", file.read(4))[0])
print file.read(counter)
attr_count -= 1
file.close()
Of course, this doesn't work at all. It produces:
GDE
2
---
é
---
ê Å
I'm completely at a loss. If anyone could show me the correct way to
do this (or at least point me in the right direction), I'd be
extremely grateful.
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