Note the parentheses after f1 and f2 in the second example. That's
what calls the functions and causes them to be evaluated and run.
- Chris
Sent from my iPod
On Sep 12, 2008, at 12:36 PM, byron <[EMAIL PROTECTED]> wrote:
I am reading o'reilly's learning python (great book), but i came
across an example (pg 291, pdf) that I am not quite understanding the
reasoning for the author's explanation:
if f1() or f2():
The author states that do to the nature of that expression, if f1()
returns True, f2() will not be evaluated.. which makes sense. His
quote:
"Here, if f1 returns a true (or nonempty) value, Python will
never run f2."
He then states:
"To guarantee that both functions will be run, call them
before the 'or':"
tmp1, tmp2 = f1(), f2()
if tmp1 or tmp2:
Being that each function is an object, a name assignment to
(tmp1,tmp2) doesn't actually evaluate or run the function itself until
the name is called.. so why would the latter example "run" both
functions as the author suggests?
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