On Sep 26, 11:19 am, Uwe Schmitt <[EMAIL PROTECTED]> wrote: > I have to parse some text which pretends to be XML. lxml does not want > to parse it, because it lacks a root element. > I think that this situation is not unusual, so: is there a way to > force lxml to parse it ?
By "pretends to be XML" you mean XML-like but not really XML? > My work around is wrapping the text with "<root>...</root>" before > feeding lxmls parser. That's actually not a bad solution, if you know that the document is otherwise well-formed. Another thing you can do is use libxml2's "recover" mode which accommodates non-well-formed XML. parser = etree.XMLParser(recover=True) tree = etree.XML(your_xml_string, parser) You'll still need to use your wrapper root element, because recover mode will ignore everything after the first root closes (and it won't throw an error). -- Mark. -- http://mail.python.org/mailman/listinfo/python-list
