On Tue, 30 Sep 2008 00:04:18 +0200, Ivan Reborin wrote:
> 1. Multi dimensional arrays - how do you load them in python For
> example, if I had:
> -------
> 1 2 3
> 4 5 6
> 7 8 9
>
> 10 11 12
> 13 14 15
> 16 17 18
> -------
> with "i" being the row number, "j" the column number, and "k" the ..
> uhmm, well, the "group" number, how would you load this ?
>
> If fortran90 you would just do:
>
> do 10 k=1,2
> do 20 i=1,3
>
> read(*,*)(a(i,j,k),j=1,3)
>
> 20 continue
> 10 continue
>
> How would the python equivalent go ?
Well, I don't know if this qualifies as equivalent:
=====
from __future__ import with_statement
from functools import partial
from itertools import islice
from pprint import pprint
def read_group(lines, count):
return [map(int, s.split()) for s in islice(lines, count)]
def main():
result = list()
with open('test.txt') as lines:
#
# Filter empty lines.
#
lines = (line for line in lines if line.strip())
#
# Read groups until end of file.
#
result = list(iter(partial(read_group, lines, 3), list()))
pprint(result, width=30)
if __name__ == '__main__':
main()
=====
The output is:
[[[1, 2, 3],
[4, 5, 6],
[7, 8, 9]],
[[10, 11, 12],
[13, 14, 15],
[16, 17, 18]]]
`k` is the first index here, not the last and the code doesn't use fixed
values for the ranges of `i`, `j`, and `k`, in fact it doesn't use index
variables at all but simply reads what's in the file. Only the group
length is hard coded in the source code.
Ciao,
Marc 'BlackJack' Rintsch
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