On Thu, 02 Oct 2008 15:39:55 -0700, Chris Rebert wrote: > On Thu, Oct 2, 2008 at 3:20 PM, Larry Bates <[EMAIL PROTECTED]> > wrote: >> a = set([1,2,3,4,5]) >> del a[1] > > Sets don't support subscripting, so if you can't go 'a_set[something]', > why would you expect to be able to be able to 'del' such an expression? > What would the subscription even mean without the 'del'? It doesn't make > sense and would just be inconsistent.
Then add subscription access too. By aliasing `__getitem__()` to `__contains__()`. And `__setitem__()` could be implemented to add or remove objects by assigning truth values. So hypothetically: >>> a = set([1, 2, 3]) >>> a[1] True >>> a[4] False >>> a[2] = False >>> a set([1, 3]) >>> a[4] = True >>> a set([1, 3, 4]) >>> del a[1] >>> a set([3, 4]) I wouldn't want that addition to `set`\s but at least it can be implemented without introducing inconsistencies. Ciao, Marc 'BlackJack' Rintsch -- http://mail.python.org/mailman/listinfo/python-list