brasse wrote:
> with nested(Foo('a'), Foo('b', True)) as (a, b):
> print a.tag
> print b.tag
If been watching this thread for a while, and I think that your problems
will go away if you write actual nested with-blocks:
with Foo("a") as a:
with Foo("b") as b:
print a.tag
print b.tag
Why look for a complex solution if there is a simple one?
Peter
--
http://mail.python.org/mailman/listinfo/python-list
