> print output.decode('utf-8')
> File "C:\Python25\lib\encodings\utf_8.py", line 16, in decode
> return codecs.utf_8_decode(input, errors, True)
> UnicodeEncodeError: 'ascii' codec can't encode character u'\xe2' in
> position 47:
> ordinal not in range(128)
Notice that it complains about the 'ascii' codec, when you were using
the utf-8 codec. Also, it complains about *en*coding, when you try
decoding.
For this, there could be two possible causes:
1. output is already a Unicode object - decoding it is not a meaningful
operation. So Python first *en*codes it with ascii, then would decode
it with UTF-8. The first step fails.
2. decoding from utf-8 works fine. It then tries to print output, which
requires an encoding. By default, it encodes as ascii, which fails.
> ========
>
> Here's the code:
> ========
> try:
> output = "Different: (%s) %s : %s # %s" %
> (id[2],id[3],id[0],id[1])
Add
print type(output)
here. If it says "unicode", reconsider the next line
> print output.decode('utf-8')
Regards,
Martin
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