jeff <[EMAIL PROTECTED]> wrote: >>>> list >[['a', [], []], ['b', [1, 2], []], ['c', [3, 4], [5, 6]]] >>>> list.index(['b',[],[]]) > >ie, would like to match the second element in the list with something >where i just know 'b' is the first element, but have no idea what the >other elements will be: > >Traceback (most recent call last): > File "<stdin>", line 1, in <module> >ValueError: list.index(x): x not in list >>>> list.index(['b',[1,2],[]]) >1
If you really want to do that: py> lst.index([x for x in lst if x[0] == 'b'][0]) (Oh, yeah, don't shadow the builtin "list".) What I suspect would be far more useful is a better data structure: py> dct = dict((x[0], x[1:]) for x in lst) py> dct['b']>>> dct['b'] [[1, 2], []] Dealing with the case of more than one entry identified by 'b' is left as a problem to someone who knows what the data actually is. -- \S -- [EMAIL PROTECTED] -- http://www.chaos.org.uk/~sion/ "Frankly I have no feelings towards penguins one way or the other" -- Arthur C. Clarke her nu becomeþ se bera eadward ofdun hlæddre heafdes bæce bump bump bump
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