I need to try calling a function 5 times. If successful, move on; If
not, print an error message, and exit the program:
success = None
for i in range(5):
#Try to fetch public IP
success = CheckIP()
if success:
break
if not success:
print "Exiting."
sys.exit()
Though a bit of an abuse, you can use
if not any(CheckIP() for _ in range(5)):
print "Exiting"
sys.exit()
(this assumes Python2.5, but the any() function is easily
recreated per the docs at [1]; and also assumes the generator
creation of 2.4, so this isn't as useful in 2.3 and below)
Alternatively, you can use the for/else structure:
for i in range(5):
if CheckIP():
break
else:
print "Exiting"
sys.exit()
-tkc
[1]
http://www.python.org/doc/2.5.2/lib/built-in-funcs.html#l2h-10
.
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