willie wrote:
My code:
from time import time
def leibniz(terms):
acc = 0.0
num = 4.0 # numerator value remains constant in the series
den = 1
count = 0
start_time = 0.0
for aterm in range(terms):
nextterm = num/den * (-1)**aterm # (-1) allows fractions to
alternate
#between a + and a - value
acc = acc + nextterm
den = den + 2 #denominator increments by 2
count = count + 1
#print(count,acc)
print("Time elapsed: %f"%( time()- start_time))
return acc
The result I get is -- Time elapsed: 1227812482.390000 but I want to
know the real time this code needed to run. Using a term value of
1000 I can see from the begining to end the actual time lapse is a
little over 6 seconds. How do I get that value (6 + secs approx) as my
time lapse.
time() gives you the current time in seconds since the Epoch (1 Jan
1970). You should set start_time to time() instead of 0.0 at the start.
Note that this will give you the elapsed time, not the CPU time. If you
want the CPU (processing) time then use clock().
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