On Dec 12, 8:08 am, "Filip Gruszczyński" <grusz...@gmail.com> wrote: > I am not doing it, because I need it. I can as well use "if not elem > is None", but I just wanted to know, if there is some better way of > doing this. I like to know :-) > > And I can't understand why you are becoming so aggressive because of > this. Just because I asked for that, doesn't mean, that I will put > some obfuscated code into my project. I just wanted to learn something > new - I checked itertools, I googled a bit, now I wanted to ask here > if someone knew some really cool way of this. All the other > assumptions weren't really necessary. > > Thanks for those ideas, however. I like the last one a lot :) > > -- > Filip Gruszczyński
In this case the "cool" way is the straightforward way: either the list versions: [x fox x in seq if x is not None] filter(lambda x: x is not None, seq) or the generator versions: (x for x in seq if x is not None) itertools.ifilter(lambda x: x is not None, seq) -- http://mail.python.org/mailman/listinfo/python-list
