Analog Kid wrote: > Hi guys: > Thanks for your responses. Points taken. Basically, I am looking for a > combination of the following ... > [^\w] and %(?!20) ... How do I do this in a single RE? > > Thanks for all you help. > Regards, > AK > > On Mon, Dec 15, 2008 at 10:54 PM, Steve Holden <st...@holdenweb.com > <mailto:st...@holdenweb.com>> wrote: > > Analog Kid wrote: > > Hi All: > > I am new to regular expressions in general, and not just re in python. > > So, apologies if you find my question stupid :) I need some help with > > forming a regex. Here is my scenario ... > > I have strings coming in from a list, each of which I want to check > > against a regular expression and see whether or not it "qualifies". By > > that I mean I have a certain set of characters that are > permissible and > > if the string has characters which are not permissible, I need to flag > > that string ... here is a snip ... > > > > flagged = list() > > strs = ['HELLO', 'Hi%20There', '123...@#@'] > > p = re.compile(r"""[^a-zA-Z0-9]""", re.UNICODE) > > for s in strs: > > if len(p.findall(s)) > 0: > > flagged.append(s) > > > > print flagged > > > > my question is ... if I wanted to allow '%20' but not '%', how > would my > > current regex (r"""[^a-zA-Z0-9]""") be modified? > > > The essence of the approach is to observe that each element is a > sequence of zero or more "character", where character is "either > letter/digit or escape." So you would use a pattern like > > "([a-zA-Z0-9]|%[0-9a-f][0-9a-f])+" > > Did you *try* the above pattern?
regards Steve -- Steve Holden +1 571 484 6266 +1 800 494 3119 Holden Web LLC http://www.holdenweb.com/ -- http://mail.python.org/mailman/listinfo/python-list
