The hack given by Peter works fine, except in this case: >>> def aaaa(fn): ... f2 = lambda x,y:(x,y,fn(x,y)) ... function = type(f2) ... f3 = function(f2.func_code,dict()) ... print f3 ... >>> aaaa(lambda x,y:x+y) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "<stdin>", line 4, in aaaa TypeError: arg 5 (closure) must be tuple >>>
Strange... 2008/12/17 Peter Otten <__pete...@web.de>: > Juan Pablo Romero Méndez wrote: > >> Suppose this function is given: >> >> def f(x,y): >> return x+y+k >> >> >> Is it possible to somehow assign a value to k without resorting to >> making k global? > > You can replace the function's global dictionary: > >>>> def f(x, y): > ... return x+y+k > ... >>>> function = type(f) >>>> function(f.func_code, dict(k=1))(2, 3) > 6 >>>> k > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > NameError: name 'k' is not defined > > This is a hack, of course. > > Peter > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list
