Aaron Brady wrote:
On Dec 21, 10:58 am, MRAB <goo...@mrabarnett.plus.com> wrote:
Aaron Brady wrote:
On Dec 21, 10:31 am, MRAB <goo...@mrabarnett.plus.com> wrote:
snip
The original format is a string. The result of '%' is a string if
there's only 1 placeholder to fill, or a (partial) format object (class
"Format"?) if there's more than one. Similarly, the format object
supports '%'. The result of '%' is a string if there's only 1
placeholder to fill, or a new (partial) format object if there's more
than one.
>>> f = "%r %i"
>>> type(f)
<type 'str'>
>>> f = f % (2, 3, 4)
>>> type(f)
<type 'Format'>
>>> f = f % 1
>>> type(f)
<type 'str'>
Alright, so how are you handling:
f= "%s %i"
type( f )
<type 'str'>
f= f% '%i' #now '%i %i'
type( f )
<type 'Format'>
f= f% 1
type( f )
?
In other words, are you slipping '1' in to the very first available
slot, or the next, after the location of the prior?
Let's assume that Format objects display their value like the equivalent
string format:
>>> f = "%r %i"
>>> f
'%r %i'
>>> f = f % (2, 3, 4)
>>> f
<Format '(2, 3, 4) %i'>
>>> f = f % 1
>>> f
'(2, 3, 4) 1'
>>>
>>> f = "%s %i"
>>> f
'%s %i'
>>> f = f % '%i'
>>> f
<Format '%%i %i'>
>>> f = f % 1
>>> f
'%%i 1'
I assume you meant '%i 1' since there are no more flags in f, and it's
returned to a regular string.
Correct.
'f %= 1' doesn't work any more as in-place modulo, since one time, 'f'
is a Format object, the other, 'f' is a string. Just raise an
exception for that (or assign to __class__ IINM if I'm not mistaken).
All assignments rebind, even the augmented form:
>>> class C1(object):
def __mod__(self, value):
return C2()
>>> class C2(object):
def __mod__(self, value):
return C2()
>>> f = C1()
>>> f
<__main__.C1 object at 0x00D144F0>
>>> f % 0
<__main__.C2 object at 0x00D143F0>
>>> f %= 0
>>> f
<__main__.C2 object at 0x00D145B0>
Actually, the class you showed is kind of nifty. Tuples are correctly
interpolated. I think on the whole you'll use more parenthesis, since
each term in the tuple appears separately, and might be an expression
(have a lower-precedence op.), as well as more modulo signs.
You can currently do-it-yourself, you just need a constructor in the
format string.
f = Format("%r %i")
type(f)
<type 'Format'>
f = f % (2, 3, 4)
type(f)
<type 'Format'>
Or, as someone suggested earlier, a new literal marking:
Yes, I suggested that earlier, but it isn't needed because you can
create a format object with "Format(string)". However, most of the time
you won't bother to create a format object explicitly because of:
class str(object):
def __mod__(self, value):
return Format(self) % value
f = f"%r %i"
type(f)
<type 'Format'>
>>> # Explicitly
>>> f = Format("%r %i")
>>> f
<Format '%r %i'>
>>> f % (2, 3, 4)
<Format '(2, 3, 4) %i'>
>>>
>>> # Implicitly, relying on the __mod__ method of str
>>> f = "%r %i"
>>> f
'%r %i'
>>> f % (2, 3, 4)
<Format '(2, 3, 4) %i'>
I'd also like to add that there's nothing to prevent format objects from
having other methods where multiple placeholders can be filled in one call:
>>> # By position
>>> f = Format("%r %i")
>>> f
<Format '%r %i'>
>>> f.fill([(2, 3, 4), 1])
'(2, 3, 4) 1'
>>>
>>> # By name
>>> f = Format("%{tuple}r %{int}i")
>>> f
<Format '%{tuple}r %{int}i'>
>>> f.fill({"tuple": (2, 3, 4), "int": 1})
'(2, 3, 4) 1'
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