On Mon, Dec 22, 2008 at 1:47 AM, Barak, Ron <ron.ba...@lsi.com> wrote:
> Hi All,
>
> I want to use generators to print lines taken from a gzipped file.
> I've never used generators, so probably my problem is basic misunderstanding
> of generators.
>
> In the below program, I expected the last line ("print line_") to print the
> first line of the sac.log.gz file.
> Instead, I get:
>
> <generator object at 0x00B93A08>
>
> Could you tell me what I'm doing wrong (or point me to a URL that could set
> me straight) ?
>
> Thanks,
> Ron.
>
>
> $ cat LogManager_try.py
> #!/usr/bin/env python
>
> import gzip
> import os
>
> class LogStream():
> """
> """
>
> def __init__(self, filename):
> self.filename = filename
> self.input_file = self.open_file(filename)
>
> def open_file(self, in_file):
> """
> The gzip module checks if the input file is a gzipped file, only at
> the read stage.
> This is why the f.readline() is needed.
> """
> try:
> f = gzip.GzipFile(in_file, "r")
> f.readline()
> except IOError:
> f = open(in_file, "r")
> f.readline()
>
> f.seek(0)
> return(f)
>
> def next_line(self, in_file):
> """
> """
> for line_ in in_file:
> yield line_.strip()
>
> if __name__ == "__main__":
> filename = "sac.log.gz"
> log_stream = LogStream(filename)
generator = log_stream.next_line(log_stream.input_file) #create generator
line_ = generator() #get next item from generator
print line_
And as you can see, this makes next_line a bit of a misnomer.
Cheers,
Chris
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