Hi Gabriel, > in Python 3.0 keys() behaves as iterkeys() in previous versions, so the above > code is supposed to be written in Python 2.x)
I understand. Thank you. > note that dict comprehensions require Python 3.0 I'm relieved to know that I didn't miss that feature in my reading of Python's 2.5/2.6 documentation :) > You might use instead: > > dict((key,(dict1[key],dict2[key])) for key in ...) Excellent. Thank you. Regards, Malcolm ----- Original message ----- From: "Gabriel Genellina" <gagsl-...@yahoo.com.ar> To: python-list@python.org Date: Wed, 24 Dec 2008 07:10:16 -0200 Subject: Re: Strategy for determing difference between 2 very large dictionaries En Wed, 24 Dec 2008 06:23:00 -0200, <pyt...@bdurham.com> escribió: > Hi Gabriel, > > Thank you very much for your feedback! > >> k1 = set(dict1.iterkeys()) > > I noticed you suggested .iterkeys() vs. .keys(). Is there any advantage > to using an iterator vs. a list as the basis for creating a set? I You've got an excelent explanation from Marc Rintsch. (Note that in Python 3.0 keys() behaves as iterkeys() in previous versions, so the above code is supposed to be written in Python 2.x) >>> can this last step be done via a simple list comprehension? > >> Yes; but isn't a dict comprehension more adequate? >> >> [key: (dict1[key], dict2[key]) for key in common_keys if >> dict1[key]!=dict2[key]} > > Cool!! I'm relatively new to Python and totally missed the ability to > work with dictionary comprehensions. Yes, your dictionary comprehension > technique is much better than the list comprehension approach I was > struggling with. Your dictionary comprehension statement describes > exactly what I wanted to write. This time, note that dict comprehensions require Python 3.0 -- so the code above won't work in Python 2.x. (It's not a good idea to mix both versions in the same post, sorry!) You might use instead: dict((key,(dict1[key],dict2[key])) for key in ...) but it's not as readable. -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list -- http://mail.python.org/mailman/listinfo/python-list
