On Sat, 03 Jan 2009 01:52:04 +0000, alex goretoy wrote:
> Hello All,
>
> I'm doing this in my code
>
> [[v.append(j) for j in i] for i in self.value]
>
> if works and all,
Replacing "self.value" with a list of lists of ints:
>>> list_of_lists = [[1, 2, 3], [2, 4, 6]]
>>> v = []
>>> output = [[v.append(j) for j in sublist] for sublist in list_of_lists]
>>> v
[1, 2, 3, 2, 4, 6]
>>> output
[[None, None, None], [None, None, None]]
So you create two lists, one is a copy of self.value which has been
flattened, and the other is a nested list of nothing but None. What a
waste of effort if your input is large.
Why not just do the obvious for loop?
v = []
for L in list_of_lists:
for item in L:
v.append(item)
> but I need to add a if statement in the mix.
Using a for loop, it should be obvious:
v = []
for L in list_of_lists:
for item in L:
if item != 0: v.append(item)
> Can't
> seem to remember the syntax to do so and everything I've tried seems to
> fail.
If you *insist* on doing it the wrong way,
[[v.append(j) for j in i if j != 0] for i in self.value]
> How do I add a check to see if j is not int("0") then append to v
> list? Thank you in advance. -A
Is there some significance of you saying int("0") instead of 0?
--
Steven.
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