On Wed, Jan 7, 2009 at 11:09 AM, Chris Rebert <c...@rebertia.com> wrote: > On Tue, Jan 6, 2009 at 6:56 PM, Steven Woody <narkewo...@gmail.com> wrote: >> Hi, >> >> I am trying define an Exception as below: >> >> class MyError(Exception): >> def __init__(self, message): >> self.message = message >> >> And, I expect that when I raise a MyError as >> raise MyError, "my message" >> the python should print a line such as >> MyError: my message >> >> But I did not get that, I just got: >> ... >> MyError >> >> I guess I had made something wrong with the __init__() definition, but >> I can not find an answer in doc. Please help, thanks! > > You need to call the superclass constructor: > > #note: this code will be different in Py 3.0 > class MyError(Exception): > def __init__(self, message): > super(MyError, self).__init__(message)
Thank you, I forgot to call base class's __init__() > > Or if you're not going to add anything else to MyError, you might as > well just leave the class body empty and it'll use Exception's > __init__, which takes care of the message. Yes, I know that, I just want to try and learn something. -- http://mail.python.org/mailman/listinfo/python-list
