Try:
import urllib2, urllib
formdata = urllib.urlencode({'a':1,'b':2})
request = urllib2.Request(url)
request.add_data(formdata)
opener = urllib2.build_opener(urllib2.HTTPSHandler())
urllib2.install_opener(opener)
fs = urllib2.urlopen(request)
https_response = fs.read()
https_headers = fs.info().headers
https_mimetype = fs.info().type-jag
<<inline: Pasted Graphic.tiff>>
Joshua Ginsberg -- [EMAIL PROTECTED] Brainstorm Internet Network Operations 970-247-1442 x131 On Apr 8, 2005, at 2:13 PM, Hasan D wrote:
I'm new on this httplib and urllib. Actually I dont know what should i use.
I want to fill the form in a "https" page , and return the result . I write a test code but always gives errors. I cant find any good example about this on the net. What should I do about this ?
import urlparse,urllib,httplib,string,htmllib,formatter
#port="443" target="https://www.abc.com/"; params = urllib.urlencode({'spam': 1, 'eggs': 2, 'bacon': 0}) http=httplib.HTTP("https://www.abc.com/",443)
data='Name=x&Adress=x' headers = {"Content-type": "application/x-www-form-urlencoded","Accept": "text/plain"}
print "Sending Data On "+target+"...\n" http.putrequest("POST",target+"/xxx.asp?q=7&b=11",params)
response = http.getresponse() print response.status, response.reason
http.send(data)
code,msg,headers = http.getreply()
print "HTTP Code : ",str(code) print "HTTP Connection : ",msg print "HTTP headers : \n",headers,"\n"
HTML=http.getfile().read() MyParser=htmllib.HTMLParser(formatter.NullFormatter()) MyParser.feed(HTML) # Print all the anchors from the results page print MyParser.anchorlist -- http://mail.python.org/mailman/listinfo/python-list
-- http://mail.python.org/mailman/listinfo/python-list
