RajNewbie wrote:
On Jan 12, 6:51 pm, Tim Chase <python.l...@tim.thechases.com> wrote:
[a perfectly fine reply which is how I'd solve it]
>> RajNewbie wrote:
... The solution that I had in mind is:
while True:
...
if <condition>: break
if inifinte_loop(): raise infiinte_loop_exception
Wherein infinite_loop is a generator, which returns true if i > 200
def infinite_loop():
i = 0
while i < 200:
i++
yield False
yield True
Could somebody let me know whether this is a good option?
...
But, I still feel it would be much more aesthetically pleasing if I
can call a single procedure like
if infinite_loop() -> to do the same.
Is it somehow possible? - say by using static variables, iterators --
anything?
1) Please cut down quoted text to as little as needed to
understand the reply.
Yes, it is possible. After:
def Fuse(count, exception):
for i in range(count):
yield None
raise exception
You can do your loop as:
check_infinite = Fuse(200, ValueError('Infinite Loop')).next
while True:
...
check_infinite()
but I agree with Tim that a for ... else loop for the limit is clearer.
--Scott David Daniels
scott.dani...@acm.org
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