En Wed, 28 Jan 2009 01:36:57 -0200, Steve Holden <st...@holdenweb.com>
escribió:
Gabriel Genellina wrote:
En Tue, 27 Jan 2009 22:17:16 -0200, Robert Kern <robert.k...@gmail.com>
escribió:
I *thought* I did understand this until I came to this example:
1)
id(globals()), id(locals())
(11239760, 11239760)
# ok, globals and locals are the same at the module level
2)
s = "(id(n) for n in [globals(),locals()])"
list(eval(s))
[11239760, 11239760] # still the same results
3)
s = "(id(n()) for n in [globals,locals])"
list(eval(s))
[11239760, 12583248] # locals() is different
No, locals is different, not locals(). You are looking at two different
functions that return the same object when called in the given context,
that's all.
Perhaps you didn't notice that I shifted the () from right to left. I'm
always printing the result of *calling* globals and locals -- the only
change is *where* I do call them.
[id(n) for n in [globals(),locals()]]
[11239760, 11239760]
[id(n()) for n in [globals,locals]]
[11239760, 12583248]
Seems that it is important *when* those functions are evaluated, but I
don't understand *why*...
--
Gabriel Genellina
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