En Wed, 28 Jan 2009 20:49:14 -0200, Muddy Coder <cosmo_gene...@yahoo.com>
escribió:
My previous post got a many helps from the people, and I tested what
they suggested. Since this topic maybe needed in future, so I drop
these lines below to help the future programmers. The methods worked
as below:
1. This method was suggested by Cameron Laird:
os.system("start %s" % URL)
It works. But, if the URL contains character &, it will fail. For
2. The best way is to use urllib2, suggested by Ron Barak, my code is
below:
import urllib2
source = urllib2.urlopen(URL).read()
print source
Note that both methods are essencially different. The first one opens a
browser window, and it's up to the user what to do after the initial
request is done -- if this is what you want, the webbrowser module is
better suited for that task.
The second one is a pure programming interfase - the Python script is in
control, and the user isn't involved at all.
--
Gabriel Genellina
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