I guess what I am saying is that it does not seem like I am adding any information that is not already there when I have to enter that list and list name after all they are the same. Thanks Vincent Davis
On Wed, Feb 4, 2009 at 10:18 AM, Vincent Davis <vinc...@vincentdavis.net>wrote: > I know nothing but that sucks. I can think of a lot of times I would like > to do something similar. There really is no way to do this, it seems like > there would be some simple way kind of like str(listname) but backwards or > different. > Thanks > Vincent Davis > > > > > On Wed, Feb 4, 2009 at 10:07 AM, MRAB <goo...@mrabarnett.plus.com> wrote: > >> Vincent Davis wrote: >> > Sorry for not being clear I would have something like this x = [1, 2, >> > 3,5 ,6 ,9,234] >> > >> > Then def savedata(dataname): .......... >> > >> > savedata(x) >> > >> > this would save a to a file called x.csv This is my problem, getting >> > the name to be x.csv which is the same as the name of the list. >> > >> > and the data in the file would be 1,2,3,5,6,9,234 this parts works >> > >> The list itself doesn't have a name. You need to pass in both the name >> and the list: >> >> def savedata(name, data): .......... >> >> savedata("x", x) >> >> -- >> http://mail.python.org/mailman/listinfo/python-list >> > >
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