Gerard Flanagan wrote:
def replace(s, patt, repls):
def onmatch(m):
onmatch.idx += 1
return repls[onmatch.idx]
onmatch.idx = -1
return patt.sub(onmatch, s)
test = """
abcTAG TAG asdTAGxyz
"""
REPLS = [
'REPL1',
'REPL2',
'REPL3',
]
print replace(test, re.compile('TAG'), REPLS)
--
or better:
import re
def replace(s, patt, repls):
repls = iter(repls)
return patt.sub(lambda m: repls.next(), s)
test = """
abcTAG TAG asdTAGxyz
"""
def repls(tag):
i = 0
while True:
i += 1
yield tag + str(i)
print replace(test, re.compile('TAG'), repls('REPL'))
--
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