gert wrote: > Can you first explain why x stay's 0 please and how i should update x > using threads ? > > from tkinter import * > from _thread import start_new_thread > from time import sleep > > x=0 > def weegbrug(x): > while True: > x=x+1 > sleep(0.5) > start_new_thread(weegbrug,(x,)) > > root = Tk() > v = StringVar() > v.set("00000") > txt = Label(root, textvariable=v, width=800, height=600, bg="yellow", > font=("Helvetica", 300)) > txt.pack(expand=YES, fill=BOTH) > root.title("Weegbrug") > root.after(500, lambda:v.set(x)) > root.mainloop() > The reason x stays at zero has nothing to do with threading.
The statement x=x+1 (which, by the way, should stylistically be written x = x + 1 if you want your code to be readable) doesn't change anything outside the function. Function arguments are values: since x is a parameter of the function, it exists only inside the function call's namespace. regards Steve -- Steve Holden +1 571 484 6266 +1 800 494 3119 Holden Web LLC http://www.holdenweb.com/ -- http://mail.python.org/mailman/listinfo/python-list