On Thu, 19 Feb 2009 16:37:49 +0000, Tim Wintle <tim.win...@teamrubber.com>
wrote:
Was wondering if someone could point out what the stupid thing I'm doing
wrong is:
{{{
import os, time
def run_multi_proc():
server_send, logger_recieve = os.pipe()
You got server_send and logger_receive backwards (also, i before e *except*
after c et cetera). Flip 'em around and all is well.
pid = os.fork()
if pid == 0:
# we are the logger
#os.close(server_send)
logger_recieve = os.fdopen(logger_recieve)
time.sleep(20)
else:
# we are the server
#os.close(logger_recieve)
server_send = os.fdopen(server_send,"w")
time.sleep(3)
os.kill(pid,signal.SIGTERM)
if __name__ == "__main__":
run_multi_proc()
}}}
python test.py
Traceback (most recent call last):
File "test.py", line 20, in <module>
run_multi_proc()
File "test.py", line 9, in run_multi_proc
logger_recieve = os.fdopen(logger_recieve)
OSError: [Errno 22] Invalid argument
Traceback (most recent call last):
File "test.py", line 20, in <module>
run_multi_proc()
File "test.py", line 15, in run_multi_proc
server_send = os.fdopen(server_send,"w")
OSError: [Errno 22] Invalid argument
really confused about why this isn't working - running on Linux with
python 2.5.2
Jean-Paul
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