In article <mailman.277.1235073073.11746.python-l...@python.org>,
"andrew cooke" <and...@acooke.org> wrote:
> i wonder what fraction of people posting with "bug?" in their titles here
> actually find bugs?
IMHO it ought to be an invariant that len(r.split(s)) should always be
one more than len(r.findall(s)).
> anyway, how about:
>
> re.findall('[A-Z]?[a-z]*', 'fooBarBaz')
>
> or
>
> re.findall('([A-Z][a-z]*|[a-z]+)', 'fooBarBaz')
That will do it. Thanks!
rg
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