Steven D'Aprano wrote:
Colin J. Williams wrote:
Sometimes, it's useful to be able to
obtain the data in the sorted sequence.
You might consider adding functionality
like:
def seqItems(self):
'''To return the items, sorted
by key. '''
return [self[k] for k in
self.seqKeys()]
Amazingly, the Python time-machine provides such functionality! Using just a
handful of pre-existing pieces, you can do this:
sorted(mydict.items())
sorted(mydict.keys())
[mydict[x] for x in sorted(mydict.keys)]
and any other sequence you might need. That's the beauty of a general
purpose programming language. You don't need everything to be a built-in
*wink*
Thanks, you are right, you have a neat
way of handling the first two, they
work with an instance of Raymond
Hettinger's. OrderedDict.
The third suggestion has a couple of
problems, which are fixed below.
if __name__ == '__main__':
d=
OrderedDict.fromkeys('abracadabra',
value= 'zzz')
print(d)
print(d.seqKeys())
print(d.seqItems())
print(d.seqValues())
# Steven D'Aprano's alternative
mydict= d.copy()
print sorted(mydict.items())
print sorted(mydict.keys())
# print [mydict[x] for x in
sorted(mydict.keys)] Instance object is
not iterable
print(sorted(iter([(x[1], x[0]) for
x in mydict.iteritems()]))) # This works
Colin W.
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