On Tue, Mar 10, 2009 at 11:34 PM, Coonay <fla...@gmail.com> wrote: > i use python2.6 > > > File "C:\PROGRA~1\Python26\lib\urllib2.py", line 383, in open > response = self._open(req, data) > File "C:\PROGRA~1\Python26\lib\urllib2.py", line 401, in _open > '_open', req) > File "C:\PROGRA~1\Python26\lib\urllib2.py", line 361, in > _call_chain > result = func(*args) > File "C:\PROGRA~1\Python26\lib\urllib2.py", line 690, in <lambda> > meth(r, proxy, type)) > File "C:\PROGRA~1\Python26\lib\urllib2.py", line 713, in proxy_open > return self.parent.open(req) > File "C:\PROGRA~1\Python26\lib\urllib2.py", line 383, in open > response = self._open(req, data) > File "C:\PROGRA~1\Python26\lib\urllib2.py", line 406, in _open > 'unknown_open', req) > File "C:\PROGRA~1\Python26\lib\urllib2.py", line 361, in > _call_chain > result = func(*args) > File "C:\PROGRA~1\Python26\lib\urllib2.py", line 1163, in > unknown_open > raise URLError('unknown url type: %s' % type) > urllib2.URLError: <urlopen error unknown url type: "http>
A. Please include the *entire* traceback, in the future B. Please include a snippet of the code you're using, in the future C. A bit less curt of a missive would also be appreciated That all said, judging by the error message, it appears that the URL you're trying to open has a double-quote (") as its first character, which is obviously not permissible. I can't be completely sure however, since you neglected to include the entire traceback or any of your actual code. Cheers, Chris -- I have a blog: http://blog.rebertia.com -- http://mail.python.org/mailman/listinfo/python-list