alex goretoy wrote:
ok now for the final result, i decided to split options out to a
separate dict of lists, does this look right to every one, I currently
have error somewhere else in my code so can't test this right now, Is
this a good method to do this? or is there another option?
[snip]
First of all, *don't use "is" and "is not" to test for equality*; use
"==" and "!=".
When you split the options out like that you get duplication.
You have, for example:
...
"colors": ["c", "cl", "col", ...]
...
and:
...
"imp_colors": ["c", "cl", "col", ...]
...
Couldn't you put them into one dict, something like:
...
"colors": ("imp_colors", ["c", "cl", "col", ...])
...
--
http://mail.python.org/mailman/listinfo/python-list
