Re: Pattern Matching Given # of Characters and no String Input; use RegularExpressions?

[tiissa]

tiissa wrote:
If you know the number of characters to match can't you just compare 
slices?
If you don't, you can still do it by hand:
In [7]: def cmp(s1,s2):
  ....:     diff_map=[chr(s1[i]!=s2[i]) for i in range(min(len(s1), 
len(s2)))]
  ....:     diff_index=''.join(diff_map).find(chr(True))
  ....:     if -1==diff_index:
  ....:         return min(len(s1), len(s2))
  ....:     else:
  ....:         return diff_index
  ....:

In [8]: cmp('cccat','cccap')
Out[8]: 4
In [9]: cmp('ccc','cccap')
Out[9]: 3
In [10]: cmp('cccat','dddfa')
Out[10]: 0
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