Mark Tarver <dr.mtar...@ukonline.co.uk> writes: > Ah; so this > > def cons (x,y): > return [x] + y > > is not accurate?
Depends what you mean by accurate! in lisp, if you do: (setq a '(1 2)) (setq b (cons 0 a)) (rplaca a 3) Then a is now (3 2) b is now (0 3 2) In Python, if you do: a = [1, 2] b = cons(0, a) # with your definition of cons a[0] = 3 Then a is now [3, 2] b is now [0, 1, 2] So in this respect, it is not accurate. But that's because Python lists are vectors not conses. -- Arnaud -- http://mail.python.org/mailman/listinfo/python-list