On Wed, May 13, 2009 at 2:50 PM, kj <[email protected]> wrote:
>
>
> Suppose I have the following:
>
> def foo(x=None, y=None, z=None):
> d = {"x": x, "y": y, "z": z}
> return bar(d)
>
> I.e. foo takes a whole bunch of named arguments and ends up calling
> a function bar that takes a single dictionary as argument, and this
> dictionary has the same keys as in foo's signature, so to speak.
>
> Is there some builtin variable that would be the same as the variable
> d, and would thus obviate the need to explicitly bind d?
def foo(**kwargs):
return bar(kwargs)
I would suggest you read the Python tutorial.
Cheers,
Chris
--
http://blog.rebertia.com
--
http://mail.python.org/mailman/listinfo/python-list
