On May 20, 12:55 am, Laurent Luce <laurentluc...@yahoo.com> wrote:
> I had a simple loop stripping each string but I was looking for
> something concise and efficient. I like the following answer:
> x = [s.rstrip('\n') for s in x]Your initial requirement stated that you needed this to happen in- place. What you're doing here is creating a completely new list and then assigning it to x. While this is most likely what you want, note that this will not update any other reference to that list: >>> x = ['test\n', 'test2\n', 'test3\n'] >>> y = x >>> x = [s.rstrip() for s in x] >>> x ['test', 'test2', 'test3'] >>> y ['test\n', 'test2\n', 'test3\n'] To perform the same operation in-place, you can use the slice operator to assign to the list object rather than to the label: >>> x = ['test\n', 'test2\n', 'test3\n'] >>> y = x >>> x[:] = [s.rstrip() for s in x] # note the slice operator >>> x ['test', 'test2', 'test3'] >>> y ['test', 'test2', 'test3'] The latter example is especially important if you have more than one reference to the list you're modifying and wish them all to have the updated value. -- http://mail.python.org/mailman/listinfo/python-list
