A python novice writes..... Hello,
I'm trying to extract certain frames from a stack of images as part of a project. In order to do this I need to produce an array which consists of a group of eight, then misses the next 8, then selects the next eight etc. i.e (0, 1, 2, 3, 4, 5, 6, 7, 16, 17,18, 19,20,21, 22, 23, 32,33,.... etc) The following code will produce a series of arrays: a = arange (0,512) b = [a[i:i + 8] for i in range (0, len(a), 16)] [array([0, 1, 2, 3, 4, 5, 6, 7]), array([16, 17, 18, 19, 20, 21, 22, 23]), array([32, 33, 34, 35, 36, 37, 38, 39]), array([48, 49, 50, 51, 52, 53, 54, 55]), array([64, 65, 66, 67, 68, 69, 70, 71]), array([80, 81, 82, 83, 84, 85, 86, 87]), etc... unfortunately I can't work out a way of joining then into a single array. Alternatively is there a simpler way of producing the array above? Thanks Graham. http://surelythatcantberight.blogspot.com/ -- http://mail.python.org/mailman/listinfo/python-list