Tim Wintle wrote:
On Fri, 2009-05-22 at 13:19 +0200, Andre Engels wrote:
number/total = 998/999 = 0
number/total*100 = 0*100 = 0
float(number/total*100) = float(0) = 0.0
Change "float(number/total*100)" to "float(number)/total*100" and it
should work:
I'd use:
(number * 100.)/total
- works because
<int> * <float> => <float>
It's a minor thing, but it's much faster to cast implicitly as you miss
the python function call overhead - it's no extra work to write, and for
numerical things it can really speed things up.
a = timeit.Timer("float(200)/5*100")
b = timeit.Timer("(200*100.)/5")
a.timeit(10000000)
12.282480955123901
b.timeit(10000000)
3.6434230804443359
Tim W
It's the old-timer in me, but I'd avoid the float entirely. You start
with ints, and you want to end with ints. So simply do the multiply
first, then the divide.
number * 100/total
will get the same answer.
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