Hi Dhananjay,
Sort has several optional arguments, the function's signature is as follows:
s.sort([cmp[, key[, reverse]]])
If you store your data as a list of lists, to sort by the third column
you could do something like:
data.sort(None, lambda x : x[2])
For more complex sortings, as the one you propose, you need to define
a compare function, that determines if an object preceeds another or
not. In your case, something like:
def list_cmp( a, b) :
if a[2] > b[2] :
return 1
elif a[2] < b[2] :
return -1
else : # a[2] == b[2]
if a[5] > b[5] :
return 1
elif a[5] < b[5] :
return -1
else : # a[5] == b[5]
return 0
data.sort(list_cmp)
should do the trick for you...
Jaime
On Mon, May 25, 2009 at 9:29 AM, Dhananjay <dhananjay.c.jo...@gmail.com> wrote:
> Hello All,
>
> I have data set as follows:
>
> 24 GLU 3 47 LYS 6 3.909233 1
> 42 PRO 5 785 VAL 74 4.145114 1
> 54 LYS 6 785 VAL 74 4.305017 1
> 55 LYS 6 785 VAL 74 4.291098 1
> 56 LYS 7 785 VAL 74 3.968647 1
> 58 LYS 7 772 MET 73 4.385121 1
> 58 LYS 7 778 MET 73 4.422980 1
> 58 LYS 7 779 MET 73 3.954990 1
> 58 LYS 7 785 VAL 74 3.420554 1
> 59 LYS 7 763 GLN 72 4.431955 1
> 59 LYS 7 767 GLN 72 3.844037 1
> 59 LYS 7 785 VAL 74 3.725048 1
>
>
>
>
> I want to sort the data on the basis of 3rd column first and latter want to
> sort the sorted data (in first step) on the basis of 6th column.
>
> I tried sort() function but could not get the way how to use it.
>
> I am new to programming, please tell me how can I sort.
>
> Thanking you in advance ........
>
> regards
>
>
>
>
> --
> --------------------------------------------------------------
> Dhananjay C Joshi
> Project Assistant
> Lab of Structural Biology,
> CDFD, Bldg.7, Gruhakalpa
> 5-4-399/B, Nampally
> Hyderabad- 500001, India
> Tel: +91-40-24749404
> Fax: +91-40-24749448
> --------------------------------------------------------------
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>
>
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