Hello, Python 2.5.2 WinXP
I'm using CGIHTTPServer.py and want to return a response code of 400 with a message in the event that the cgi script fails for some reason. I notice that run_cgi(self): executes this line of code, self.send_response(200, "Script output follows") which overwrites any headers that I print in my cgi. Is there some way to modify the response code without having to override CGIHTTPServer.py? Thanks, -- http://mail.python.org/mailman/listinfo/python-list
