Hendrik van Rooyen schrieb:
One can go from lb = ['b','a','n','a','n','a'] to s = "banana" by using s = "".join(lb)Is there a way to go the reverse route? I have not been able to find one. It is obviously easy to write a for char in s loop or list comprehension, but there seems to be no function or string method to return a list of characters. using lb = s.split("") would have been nice as a complement to s = "".join(lb). Split is already full of magic, it could do with more.
I think lb = list(s) is good enough. Diez -- http://mail.python.org/mailman/listinfo/python-list
