rom wrote:
Thanks for your response. I have modified this minimal program as you
suggested but still is not able to print the filename:
######################
import Tkinter
import tkFileDialog
global filename
# NO NO NO! No global line here
filename=''
root = Tkinter.Tk()
Tkinter.Button(root, text='Notch genes...', command=lambda:
open_file_dialog()).pack()
def open_file_dialog():
# global var goes here, inside the def so the var filename is not local
# just like I show below.
filename = tkFileDialog.askopenfilename(filetypes=
[("allfiles","*")])
print filename
root.mainloop()
######################
Is this what you mean?
On Jun 25, 1:28 pm, norseman <norse...@hughes.net> wrote:
OOPS - I left out the global statement
rom wrote:
Hi there,
I am writing an interface with Tkinter. My minimal program looks like
this:
#############
import Tkinter
import tkFileDialog
# define globals here
filename= '' # will take care of the problem
root = Tkinter.Tk()
Tkinter.Button(root, text='Notch genes...', command=lambda:
open_file_dialog()).pack()
def open_file_dialog():
global filename # need this to assign to it
filename = tkFileDialog.askopenfilename(filetypes=[("all
files","*")])
# print filename
root.mainloop()
#############
I would like to recover the filename variable outside the
"open_file_dialog" function. For instance, to be able to print the
selected file name (uncomment "# print filename" line).
Is there a way to do that?
Thanks in advance.
R
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