Scott David Daniels a écrit :
(snip)
And even simpler:
PASSWORD = "qwerty"
MAXRETRY = 3
for attempt in range(MAXRETRY):
if raw_input('Enter your password: ') == PASSWORD:
print 'Password confirmed'
break # this exits the for loop
print 'Access denied: attempt %s of %s' % (attempt+1, MAXRETRY)
else:
# The else for a for statement is not executed for breaks,
# So indicates the end of testing without a match
raise SystemExit # Or whatever you'd rather do.
Which is probably the most pythonic implementation.
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