Each function has a func_code property that is suposed to contain the pure bytecode of the function. All the context (including reference to relevant namespaces) is stored in different fields of the function object. Since 'exec' is able to execute any string or bytecode in the current scope, it would seem possible to execute code of any function in any namespace. But no matter how I tried, I could not do it. There must be something I am missing. Here's what I do: (if anyone wants to help, I placed the source under http://www.bajobongo.net/foo.py - tested on Python 2.4.1)
1. I declare a function. In the next steps I will try to run its code from inside a class: def myfunction(): print abc self.test() 2. I declare a class foo, with two methods. The first one tries to reach some local variables from a string passed to exec. The other one tries to do the same from inside a bytecode (from myfunction). IMHE this should make no difference to 'exec' - [spoiler: it does]. class foo: def test(self): print "ABC" def checkfunction(self): abc=10 exec myfunction.func_code def checkstring(self): abc=10 exec "print abc;self.test()" 3. I test the both methods. Sadly, the 'checkfunction' fails to find the correct namespace (id does not see 'abc' nor 'self'). Adding things like: "exec myfunction.func_code in globals(),locals()" does not help. i=foo() i.checkstring() i.checkfunction() # this throws exception; why??? 4. I try to find some help here, and hope to also gain better undesrtanding of how Python works :-) Thanks for any suggestions, regards, Filip Dreger -- http://mail.python.org/mailman/listinfo/python-list