Ethan Furman wrote:
Greetings!
My closest to successfull attempt:
Python 2.5.4 (r254:67916, Dec 23 2008, 15:10:54) [MSC v.1310 32 bit (Intel)]
Type "copyright", "credits" or "license" for more information.
IPython 0.9.1 -- An enhanced Interactive Python.
In [161]: re.findall('\d+','this is test a3 attempt 79')
Out[161]: ['3', '79']
What I really want in just the 79, as a3 is not a decimal number, but
when I add the \b word boundaries I get:
In [162]: re.findall('\b\d+\b','this is test a3 attempt 79')
Out[162]: []
What am I missing?
The sneaky detail that the regexp should be in a raw string
(always a good practice), not a cooked string:
r'\b\d+\b'
The "\d" isn't a valid character-expansion, so python leaves it
alone. However, I believe the "\b" is a control character, so
your actual string ends up something like:
>>> print repr('\b\d+\b')
'\x08\\d+\x08'
>>> print repr(r'\b\d+\b')
'\\b\\d+\\b'
the first of which doesn't match your target string, as you might
imagine.
-tkc
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