Sebastian Bassi wrote:
On Fri, Jul 24, 2009 at 7:28 PM, superpollo<u...@example.net> wrote:
is there a pythonic and synthetic way (maybe some standard module) to "pack"
an integer (maybe a *VERY* big one) into a string? like this:
What do you mean to pack? Maybe Pickle is what you want.
import cPickle
variable = 124348654333577698
cPickle.dump(variable,open('filename', 'w'))
To load it:
import cPickle
vaariable = cPickle.load(open('filename'))
It is not "into a string", but instead of a filename, use a string with stringio
>>> number
252509952
>>> f = cStringIO.StringIO()
>>> cPickle.dump(number , f)
>>> f.getvalue()
'I252509952\n.'
>>>
as you can see, the pickled representation is not what i wanted...
thanks anyway
bye
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