> Hi, > > I have a string as str='123ACTGAAC'. > > I need to extract the numeric part from the alphabetic part which I > did using > >>>numer=re.findall(r'\d+',str) > >>>numer > 123 > > To get the alphabetic part, I could do > >>>alpha=str.replace('123','') > >>>alpha > ACTGAAC > But when I give > >>>alpha=str.replace(numer,'') > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > TypeError: expected a character buffer object > > How do I blank out the initial numeric part so as to get just the > alphabetic part. The string is always in the same format. > > Please help. > > Regards, > Sandhya
If the format's always the same, you could use slicing instead. >>> s = '123ACTGAAC' >>> s[:3] '123' >>> s[3:] 'ACTGAAC' BTW, you should avoid using built-ins like str for variable names. Bad things will happen. Cheers, Drea -- http://mail.python.org/mailman/listinfo/python-list