goldtech wrote:
Could you explain or link me to an explanation of this? Been using
Python for a while but not sure I understand what's happening below.
Thanks.
ss=1 and "fffff"
ss
'fffff'
ss=0 and "fffff"
ss
0
Python's Boolean operators don't turn arbitrary values into True and
False values. If you use it in any conditional, you'll get the same
result as if it did, but it is occasionally it's nice to get the actual
values used in the "and" instead of having the value distilled down to a
True/False.
From the Python manual:
These are the Boolean operations, ordered by ascending priority:
Operation Result Notes
|x or y| if x is false, then y, else x (1)
|x and y| if x is false, then x, else y (1)
|not x| if x is false, then |True|, else |False| (2)
Notes:
*(1)*
These only evaluate their second argument if needed for their outcome.
*(2)*
"not" has a lower priority than non-Boolean operators, so |not a ==
b| is interpreted as |not (a == b)|, and |a == not b| is a syntax
error.
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