On Aug 18, 3:31 pm, Duncan Booth <duncan.bo...@invalid.invalid> wrote: > Robert Dailey <rcdai...@gmail.com> wrote: > > Hello, > > > I want to simply wrap a function up into an object so it can be called > > with no parameters. The parameters that it would otherwise have taken > > are already filled in. Like so: > > > print1 = lambda: print( "Foobar" ) > > print1() > > > However, the above code fails with: > > > File "C:\IT\work\distro_test\distribute_radix.py", line 286 > > print1 = lambda: print( "Foobar" ) > > ^ > > SyntaxError: invalid syntax > > > How can I get this working? > > def print1(): > print "Foobar" > > It looks like in your version of Python "print" isn't a function. It always > helps if you say the exact version you are using in your question as the > exact answer you need may vary.
I'm using Python 2.6. And using the legacy syntax in the lambda does not work either. I want to avoid using a def if possible. Thanks. -- http://mail.python.org/mailman/listinfo/python-list
