On Sep 8, 11:19 am, Dave Angel <da...@ieee.org> wrote: > Mart. wrote: > > <snip> > > I have been doing this to turn the email into a string > > > email =ys.argv[1] > > f =open(email, 'r') > > s =str(f.readlines()) > > > so FTPHOST isn't the first element, it is just part of a larger > > string. When I turn the email into a string it looks like... > > > 'FINISHED: 09/07/2009 08:42:31\r\n', '\r\n', 'MEDIATYPE: FtpPull\r\n', > > 'MEDIAFORMAT: FILEFORMAT\r\n', 'FTPHOST: e4ftl01u.ecs.nasa.gov\r\n', > > 'FTPDIR: /PullDir/0301872638CySfQB\r\n', 'Ftp Pull Download Links: \r > > \n', 'ftp://e4ftl01u.ecs.nasa.gov/PullDir/0301872638CySfQB\r\n', 'Down > > load ZIP file of packaged order:\r\n', > > <snip> > > The mistake I see is trying to turn a list into a string, just so you > can try to parse it back again. Just write a loop that iterates through > the list that readlines() returns. > > DaveA
No kidding. Instead of this: s = str(f.readlines()) ftphost = re.search(r'FTPHOST: (.*?)\\r',s).group(1) ftpdir = re.search(r'FTPDIR: (.*?)\\r',s).group(1) url = 'ftp://' + ftphost + ftpdir I would have possibly done something like this (not tested): lines = f.readlines() header={} for row in lines: key,sep,value = row.partition(':')[2].rstrip() header[key.lower()]=value url = 'ftp://' + header['ftphost'] + header['ftpdir'] -- http://mail.python.org/mailman/listinfo/python-list